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Q.

The empirical formula of a compound is ${CH}_{2} O$ . Its molecular weight is 120. The molecular formula of the compound is

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a

$C_{4} H_{8} O_{4}$

b

$C_{3} H_{6} O_{3}$

c

$C_{6} H_{12} O_{6}$

d

$C_{2} H_{4} O_{2}$

answer is B.

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Detailed Solution

Given D.F = ${CH}_{2} O & its mass = 30$

Given molar mass = 120

So, molecular formula = ${({CH}_{2} O)}_{4}$

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