The empirical formula of a non-electrolyte is CH2O. A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05M glucose solution at the same temperature. The molecular formula of the compound is

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The empirical formula of a non-electrolyte is ${CH}_{2} O .$ A solution containing $6 g$ of the compound exerts the same osmotic pressure as that of $0.05 M$ glucose solution at the same temperature. The molecular formula of the compound is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$C_{4} H_{8} O_{4}$

$C_{3} H_{6} O_{3}$

$C_{5} H_{10} O_{5}$

$C_{2} H_{4} O_{2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For isotonic solution : $\frac{w_{1}}{m_{1} V_{1}} = \frac{w_{2}}{m_{2} V_{2}}$

$w_{1} =$ mass of glucose $= 0.05 \times 180 g = 9 g$

$m_{1} =$ molecular mass of glucose $= 180 g$

Assuming $V_{1} = V_{2} = 1 L$

$w_{2} =$ mass of compound $= 6 g$

$m_{2} =$ molecular mass of compound = ?

$\begin{array}{l} ∴ \frac{9}{180} = \frac{6}{x} \Rightarrow x = 120 g \\ ∴ \frac{Molecular mass}{Empirical mass} = n \Rightarrow n = \frac{120}{30} = 4 \end{array}$