The empirical formula of Boron Hydride is BH₃. Calculate the molecular formula when the measured mass of the compound is 27.66.

Given Information:

• The empirical formula of Boron Hydride is BH₃.
• The measured mass of the compound is 27.66 g.

Step-by-Step Calculation:

1. Molar Mass of BH₃ (Empirical Formula):

First, we calculate the molar mass of the empirical formula (BH₃):

    Molar mass of BH₃ = Boron (B) + 3 x Hydrogen (H)    = 10.81 g/mol + (3 × 1.008 g/mol)    = 13.834 g/mol    

2. Calculate the Ratio of Measured Mass to Empirical Formula Mass:

Now, divide the measured mass of the compound by the molar mass of the empirical formula to find the ratio:

    Ratio = Measured mass / Empirical formula mass    = 27.66 g / 13.834 g/mol    = 2    

The ratio is 2, which means the molecular formula is 2 times the empirical formula.

3. Molecular Formula:

Multiply the empirical formula by 2 to get the molecular formula:

    Molecular formula = 2 × BH₃ = B₂H₆    

Conclusion:

The molecular formula of Boron Hydride is B₂H₆.

Correct Answer:

Option c: B₂H₆