The empirical formula of oxalic acid $(H_{2} C_{2} O_{4}) i s$

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$H_{2} C_{2} O_{2}$

${HCO}_{2}$

$H_{4} C_{4} O_{8}$

$H_{2} C_{2} O_{4}$

answer is A.

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Detailed Solution

The simplest ratio of the no of atoms of different element of a compound Gives empirical formula. Molecular formula $= H_{2} C_{2} O_{4}$

Reduce the M.F Divide the subscripts of oxalic acid by the greatest common factor.

Oxalic acid (GCF) = 2

$\frac{2}{2} \frac{2}{2} \frac{4}{2} = 1, 1, 2$

Empirical formula of oxalic acid = ${HCO}_{2}$

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