The end of a capillary tube with a radius r is immersed into water and the water rises up inside the tube in steady state (T is the surface tension and $\rho$ is the density of water).

The water rises to a height $h=\frac{2T}{\rho gr}$
The P.E of water column is $E_p=\frac{mgh}{2}=\frac{2\pi T^2}{\rho g}$
The forces of surface tension perform the work $W=2\pi rTh=\frac{4\pi T^2}{\rho g}$
One half of this work goes to increase the and the other half to evolve heat
Hence $Q=\frac{2\pi T^2}{\rho g}$.