The end $B$ of the rod $AB$ which makes an angle $\theta$ with the floor is being pulled with a constant velocity $V_0$ as shown in the figure. The length of the rod is $l$ . At the instant when $\theta =37°$

 

This equation is on example of combined rotational and translational motion, here we are solving this with the help of instantaneous axis of rotation is lying at a distance of $l\sin \theta$ from end $B$ and perpendicular to $V_0$. Let $\omega$ is the angular velocity of rod. Then.

$V_A=\omega \times l\cos \theta$ and $V_A=V_0=\omega \times l\sin \theta$