The ends of a rectangular copper rod of conductivity 0.5 CGS units and area of cross section 20 cm2 and length 10cm are kept in a steam chamber and an ice box. The mass of the ice that melts in 5 minutes is

P=Qt=100-0LKA⇒mLicet=100KAL⇒m=100KAtLiceL⇒m=100×0.5×20×5×6080×10=375 g

The ends of a rectangular copper rod of conductivity 0.5 CGS units and area of cross section 20 cm2 and length 10cm are kept in a steam chamber and an ice box. The mass of the ice that melts in 5 minutes is

P=Qt=100-0LKA⇒mLicet=100KAL⇒m=100KAtLiceL⇒m=100×0.5×20×5×6080×10=375 g

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The ends of a rectangular copper rod of conductivity 0.5 CGS units and area of cross section 20 cm² and length 10cm are kept in a steam chamber and an ice box. The mass of the ice that melts in 5 minutes is

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375 g

750 g

1 kg

1.5 kg

answer is A.

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Detailed Solution

$P = \frac{Q}{t} = \frac{100 - 0}{\frac{L}{KA}}$

$\Rightarrow \frac{{mL}_{ice}}{t} = \frac{100 KA}{L}$

$\Rightarrow m = \frac{100 KAt}{L_{ice} L}$

$\Rightarrow m = \frac{100 \times 0.5 \times 20 \times 5 \times 60}{80 \times 10} = 375 g$

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The ends of a rectangular copper rod of conductivity 0.5 CGS units and area of cross section 20 cm2 and length 10cm are kept in a steam chamber and an ice box. The mass of the ice that melts in 5 minutes is

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The ends of a rectangular copper rod of conductivity 0.5 CGS units and area of cross section 20 cm² and length 10cm are kept in a steam chamber and an ice box. The mass of the ice that melts in 5 minutes is