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Q.

The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment, the displacement of the wire is y1=AsinπxLsinωt and the energy is E1, and in another experiment its displacement is y2=A sin2πxLsin2ωt and the energy is E2 then

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a

E2 = 2E1

b

E2 = 4E1

c

E2 = 16E1

d

E2 = E1

answer is C.

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Detailed Solution

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E1E2=ω1ω22=ω2ω2

E1E2=14
E2 = 4E1

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