Q.

The ends Q and R of two thin wires, PQ and RS, are soldered (joined) together. Initially each of the wires has a length of 1 m at 100C. Now the end P is maintained at 100C, while the end S is heated and maintained at 4000C. The system is thermally insulated from its surroundings. If the thermal conductivity of wire PQ is twice that of the wire RS and the coefficient of linear thermal expansion of PQ is 1.2×105K1, the change in length of the wire PQ is

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a

0.90 mm

b

1.56 mm

c

0.78 mm

d

2.34 mm

answer is A.

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Detailed Solution

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Since, both are connected in series, rate of heat flow is same.2kAT10L=kA400TLT=1400CTemperature Gradient of PQ, Tx=140101=130So, temperature at distance x, T=10+130xConsider an element of length dx at distance x from P.Increase in its length=dL=dxαT10dL=α13001xdxL=1.2×105×130×12=78×105m=0.78mm

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The ends Q and R of two thin wires, PQ and RS, are soldered (joined) together. Initially each of the wires has a length of 1 m at 100C. Now the end P is maintained at 100C, while the end S is heated and maintained at 4000C. The system is thermally insulated from its surroundings. If the thermal conductivity of wire PQ is twice that of the wire RS and the coefficient of linear thermal expansion of PQ is 1.2×10−5K−1, the change in length of the wire PQ is