The energies $E_{1} and E_{2}$ of two electromagnetic radiations are 75 eV and 50 eV respectively. The relation between their wavelengths $λ_{1} and λ_{2}$ will be

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$λ_{1} = λ_{2}$

$λ_{1} = 2 λ_{2}$

$2 λ_{1} = 3 λ_{2}$

$λ_{1} = \frac{2}{3} λ_{2}$

answer is D.

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Detailed Solution

$E_{1} = \frac{hc}{λ_{1}} and E_{2} = \frac{hc}{λ_{2}}; \frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}} \frac{λ_{2}}{λ_{1}} = \frac{75}{50} = \frac{3}{2} λ_{1} = \frac{2}{3} λ_{2}$

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