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Q.

The energies of the incident photons are 3, 4, 5 eV.  The work functions of the metals are 0.5, 1.5, 2.5 eV. The maximum K.E.s of the photo electrons are in the ratio

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a

1 : 1 : 1   

b

5 : 3 : 1

c

3 : 4 : 5

d

1 : 3 : 5   

answer is C.

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Detailed Solution

KEmax = E – Wo ; 

\therefore  K1 = 3 – 0.5 = 2.5,

     K2= 4 – 1.5 = 2.5,

     K3= 5 – 2.5 = 2.5

\therefore K1 : K2 : K3 = 1:1:1

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