The energies of the incident photons are 3, 4, 5 eV. The work functions of the metals are 0.5, 1.5, 2.5 eV. The maximum K.E.s of the photo electrons are in the ratio

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The energies of the incident photons are 3, 4, 5 eV. The work functions of the metals are 0.5, 1.5, 2.5 eV. The maximum K.E.s of the photo electrons are in the ratio

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1 : 1 : 1

5 : 3 : 1

3 : 4 : 5

1 : 3 : 5

answer is C.

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Detailed Solution

KE_max = E – W_o ;

$\therefore$ K₁ = 3 – 0.5 = 2.5,

K₂= 4 – 1.5 = 2.5,

K₃= 5 – 2.5 = 2.5

$\therefore$ K₁ : K₂ : K₃ = 1:1:1

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