The energy density associated with electric field E and magnetic field B→ of an electromagnetic wave in free space is given by ( ∈0− permittivity of free space , μ0− permeability of free space)

U E = ∈ 0 E 2 2 , U B = μ 0 B 2 2

U E = ∈ 0 E 2 2 , U B = μ 0 B 2 2

U E = E 2 2 ∈ 0 , U B = B 2 2 μ 0

U E = ∈ 0 E 2 2 , U B = B 2 2 μ 0

U E = E 2 2 ∈ 0 , U B = μ 0 B 2 2

U E = ∈ 0 E 2 2 , U B = μ 0 B 2 2

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The energy density associated with electric field E and magnetic field $\vec{B}$ of an electromagnetic wave in free space is given by ( $\in_{0} -$ permittivity of free space , $μ_{0} -$ permeability of free space)

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$U_{E} = \frac{E^{2}}{2 \in_{0}}, U_{B} = \frac{B^{2}}{2 μ_{0}}$

$U_{E} = \frac{\in_{0} E^{2}}{2}, U_{B} = \frac{B^{2}}{2 μ_{0}}$

$U_{E} = \frac{E^{2}}{2 \in_{0}}, U_{B} = \frac{μ_{0} B^{2}}{2}$

$U_{E} = \frac{\in_{0} E^{2}}{2}, U_{B} = \frac{μ_{0} B^{2}}{2}$

answer is D.

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Energy density due to electric field
$U_{E} = \frac{1}{2} \in_{0} E^{2}$
Energy density due to magnetic field
$U_{B} = \frac{B^{2}}{2 μ_{0}}$

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