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The energy density u is plotted against the distance r from the centre of a spherical charge distribution outside it on a $\log u - \log r$ scale. The slope of the line is

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-4

-2

-1

-8

answer is C.

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Detailed Solution

$V = \frac{1}{2} \in_{0} E^{2} = \frac{1}{2} \in_{0} {(\frac{K ϕ}{r^{2}})}^{2} \Rightarrow U \times γ^{- 4} \Rightarrow \log r = - 4 \log r + K$

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