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The energy difference between the two orbits of a hydrogen atom is $Δ E = R_{\infty} h c (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) \neq$ For the Lyman series, the values of $n_{2} a n d n_{2}$ are given as

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$n_{1} = 1, n_{2} = 2, 3, 4.....$

$n_{1} = 2, n_{2} = 3, 4, 5......$

$n_{1} = 3, n_{2} = 4, 5, 6......$

$n_{1} = 4, n_{2} = 5, 6, 7.......$

answer is A.

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$n_{1} = 1, n_{2} = 2, 3, 4.....$

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