Q.

The energy flux of sunlight reaching the surface of the earth is 1.388 × 103 W/m2. How many photons (nearly) per square metre are incident on the Earth per second? Assume that the photons in the sunlight have an average wavelength of 550nm.

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a

3.84 × 1021

b

2.51 x 1021

c

1.51 × 1021

d

7.51 × 1021

answer is B.

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Detailed Solution

Step 1: Given Data

  • Energy flux of sunlight: P = 1.388 × 103 W/m2
  • Average wavelength of photons: λ = 550 nm = 550 × 10-9 m
  • Speed of light: c = 3 × 108 m/s
  • Planck's constant: h = 6.626 × 10-34 J·s

Step 2: Energy of a Single Photon

The energy of one photon is given by the formula:

Ephoton = (h × c) / λ

Substituting the values:

Ephoton = (6.626 × 10-34 × 3 × 108) / (550 × 10-9)

Result:

Ephoton = 3.61 × 10-19 J

Step 3: Number of Photons per Second per Square Meter

The number of photons can be calculated using the formula:

N = P / Ephoton

Substituting the values:

N = (1.388 × 103) / (3.61 × 10-19)

Result:

N ≈ 3.84 × 1021 photons/m2/s

Final Answer:

The number of photons incident on the Earth per square meter per second is approximately:

3.84 × 1021 photons/m2/s

 

\therefore n = \frac{{\phi At\lambda }}{{hc}} = \frac{{1.388 \times {{10}^3} \times 1 \times 1 \times 550 \times {{10}^{ - 9}}}}{{6.6 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}

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