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The energy of a photon in a monochromatic light of wavelength 621 nm matches with the band gap of a semiconducting material. Then the minimum energy required to create an electron-hole pair from the semiconductor is
[Take hc = 1242eV-nm, where h is Planck’s constanct and c is speed of light in vacuum]

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3.4 eV

1.7 eV

2 eV

2.2 eV

answer is C.

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Detailed Solution

$E_{g} = \frac{1240}{620} e V = 2 eV$

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