The energy of a photon is given as $3 .03 \times 10^{- 19}$ . The wavelength of the photon is

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656 nm

65.6 nm

0.656 nm

6.56 nm

answer is D.

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Detailed Solution

$E = \frac{hc}{λ} or λ = \frac{hc}{E}$
$λ = \frac{6 .626 \times 10^{- 34} Js \times 3 \times 10^{8} {ms}^{- 1}}{3 .03 \times 10^{- 19} J} = 6 .56 \times 10^{- 7} m or 656 nm$

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