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Q.

The energy of a photon is 3×1012 ergs. What is its wavelength in nm ?

h=6.62×1027 erg.sec;  C=3×1010Cm1s1

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a

6.62

b

66.2

c

662

d

1324

answer is A.

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Detailed Solution

E=hvE=hcλE=hvE=hcλE=3×1012 ergs h=6.625×1027ergsecC=3×1010cms1λ=hcE=6.625×1027×3×10103×1012=662.5×107cm=662.5nm,=662nm

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