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Q.

The energy of activation for a reaction is 100 kJ/mol at 57°C. Presence of catalyst lower activation energy by 25%. The rate of reaction is increased by 10x, the value of x is

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answer is 4.

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Detailed Solution

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r2r1=K2K1=A⋅e−Ea2/RTA⋅e−Ea1/RT10x=e−Ea2+ϵa2RT;2.303log10⁡10x=ϵa1−ϵa2RTx=25×10008.314×330×2.303=3.95≅4

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