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Q.

The energy of activation for the following reaction is 10KJmol1 and ' k ' is 2.40×105s1 respectively at 300 K. The temperature at which t1/2 is equal to 2 hrs will be 2N2O54NO2+O2 in CCl4 [log4=0.6021]

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a

300 K

b

320 K

c

330 K

d

458 K

answer is B.

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Detailed Solution

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Rate constant (k2) at temperature T2 is 

K2=0.6932×36009.6×10-5 sec-1

logK2K1=Ea2.303R1T1-1T2

log9.6×10-52.4×10-5=10×10002.303×8.3141300-1T2

solving T = 458.71 K 458 K

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