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Q.

The energy of an electron in n^th orbit of hydrogen atom is

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a

$\frac{13 .6}{n^{4}} eV$

b

$\frac{13 .6}{n^{3}} eV$

c

$- \frac{13 .6}{n^{2}} eV$

d

$\frac{13 .6}{n} eV$

answer is C.

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Detailed Solution

.Energy of electron in nth orbit of Hydrogen atom is given by $E_{n} = - \frac{13.6 Z^{2}}{n^{2}}$ ev

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