The energy of an electron in the first Bohr’s orbit of a hydrogen atom is$-2.18\times {10}^{-18}J$ . Its energy in the second orbit would be

$E_1=-2.18\times {10}^{-18}J$

$E_n=\frac{-2.18\times {10}^{-18}}{n^2}Jato{m}^{-1}$

$E_2=\frac{-2.18\times {10}^{-18}}{2^2}Jato{m}^{-1}$

$E_2=-0.545\times {10}^{-18}Jato{m}^{-1}$

                $E_2=5.45\times {10}^{-19}J$