The energy of an electron in the first Bohr’s orbit of a hydrogen atom is –2.18 × 10^-18J. Its energy in the second orbit would be

The energy of electron in hydrogen atom is

En=$\frac{-2.18}{{\mathrm{n}}^2}\times {10}^{-18} \mathrm{J}$

The energy in the second orbit $\frac{-2.18}{2^2}\times {10}^{-18} \mathrm{J}$

 =  -0.545 $\times$10^-18 J

(or) = -5.45 $\times$10^-19 J