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Q.

The energy of an electron present in Bohr’s second orbit of hydrogen atom is
 

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a

– 164 kJ mol–1

b

 – 328 J mol–1 

c

– 328 kJ mol–1
 

d

 –1312 J atom–1 

answer is B.

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Detailed Solution

E=-1312n2 kJ /mol for n=2  E=-131222=-328  kJ /mol

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