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Q.

The energy of one mole of photons of radiation of wavelength 400 nm (give h=6.63×1034 JsNA=6.02×1023 mol1C=3×108 mol1) (J+E)

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a

299 kJ   

b

325 kJ  mol1

c

399 kJ mol1

d

435 kJ  mol1

answer is A.

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Detailed Solution

E=nhvE=nhcλ

=6.63×1034×3×108×6.023×1023400×109

=299 kJ mol-1

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