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Q.

The energy of one mole of photons of radiation of frequency 2×1012 Hz in J  mol1 is ___(Nearest integer) [Given, h=6.626×1034Js,NA=6.022×1023mol1 ]

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a

570

b

798

c

640

d

890

answer is A.

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Detailed Solution

E=nhϑ
=6.023×1023×6.625×1034×2×1012
=798J/mol

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