The energy of photon is given as E / atom 3.03×10−19J atom−1.Then the wavelength (λ)of the photon is

ΔE=hv=hcλ∴λ=hcΔE=6.63×10−34(3×108)3.03×10−19=656nm

ΔE=hv=hcλ∴λ=hcΔE=6.63×10−34(3×108)3.03×10−19=656nm

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The energy of photon is given as E / atom $3.03 \times 10^{- 19} J a t o m^{- 1}$ .Then the wavelength $(λ)$ of the photon is

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65.6 nm

656 nm

0.656 nm

6.56 nm

answer is B.

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$Δ E = h v = \frac{h c}{λ}$

$∴ λ = \frac{h c}{Δ E} = \frac{6.63 \times 10^{- 34} (3 \times 10^{8)}}{3.03 \times 10^{- 19}} = 656 n m$

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