The energy of photon of light having frequency of 3×1015 s-1 is

E=hϑh=6.6.25×10-34 Jϑ=3×1015 s-1E=6.625×10-34×3×1015=19.86×10-19E=1.99×10-18J.

The energy of photon of light having frequency of 3×1015 s-1 is

E=hϑh=6.6.25×10-34 Jϑ=3×1015 s-1E=6.625×10-34×3×1015=19.86×10-19E=1.99×10-18J.

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The energy of photon of light having frequency of $3 \times 10^{15} s^{- 1}$ is

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$1.99 \times 10^{- 18} J$

$1.99 \times 10^{- 17} J$

$1.99 \times 10^{- 17} ergs$

$1.99 \times 10^{- 18} ergs$

answer is A.

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Detailed Solution

$E = hϑ$

$h = 6.6.25 \times 10^{- 34} J$

$ϑ = 3 \times 10^{15} s^{- 1}$

$E = 6.625 \times 10^{- 34} \times 3 \times 10^{15}$

$= 19.86 \times 10^{- 19}$

$E = 1.99 \times 10^{- 18} J .$

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The energy of photon of light having frequency of $3 \times 10^{15} s^{- 1}$ is