The energy of $\gamma$-ray photon is $E_{\gamma }$ and that of an X-ray photon is E_X. If the visible light photon has an
energy of E_v , then we can say that [WB JEE 2014]

$\because$    ${\mathrm{V}}_{\gamma }>{\mathrm{V}}_X>{\mathrm{V}}_v$         Energy of a photon = E = h $\nu$ 

as gamma rays have maximum frequency among the given rays and hence gamma photon will have maximum energy in the given photons as per the following order.  

$\therefore$We can say that,  $E_{\gamma }>E_X>E_v$.