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Q.

The energy of second Bohr orbit of hydrogen atom is –328 kJ. mol^–1, hence energy of fourth Bohr orbit would be

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a

–1312 kJ mol^–1

b

–82 kJ mol^–1

c

–164 kJ mol^–1

d

–41 kJ mol^–1

answer is B.

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Detailed Solution

$E_{n} = \frac{- Z^{2}}{n^{2}} E_{1}$

$\frac{E_{4}}{E_{2}} = \frac{(- \frac{1}{4^{2}})}{(- \frac{1}{2^{2}})} (∵ Z = 1)$

$\frac{E_{4}}{E_{2}} = \frac{1}{4}$

$E_{4} = \frac{E_{2}}{4}$

$= \frac{- 328}{4} = - 82 KJ / mole$

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The energy of second Bohr orbit of hydrogen atom is –328 kJ. mol–1, hence energy of fourth Bohr orbit would be