The energy of second Bohr orbit of hydrogen atom is 1 -328kJ. ${\mathrm{mol}}^{-1}$ , hence energy of fourth Bohr orbit would be

The energy of hydrogen atom in Bohr’s orbit is 

${\mathrm{E}}_{\mathrm{a}}=\frac{-1312}{{\mathrm{n}}^2}{\mathrm{KJmol}}^{-1}$

For hydrogen atom, the ratio of energy between two different orbits is

$\frac{{\mathrm{E}}_1}{{\mathrm{E}}_2}=\frac{n_2^2}{n_1^2}; then \frac{E_4}{E_2}=\frac{2^2}{4^2}$

${\mathrm{E}}_4=\frac{2^2}{2^2}\times {\mathrm{E}}_2=\frac{2^2}{4^2}\times \left(-328\mathrm{KJ}.{\mathrm{Mol}}^{-1}\right)$

$\therefore {\mathrm{E}}_4=-82{\mathrm{KJmol}}^{-1}$

As we going away from nucleus magnitude of energy increases.