The energy required to break one mole of Cl – Cl bonds in $C_{12}$ is 242 kJ $m o l^{- 1}$ . The longest wavelength of light capable of breaking a single Cl – Cl bond is $(c = 3 \times 10^{8} m s^{- 1} a n d N_{A} = 6.02 \times 10^{23} m o l^{- 1})$

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640 nm

494 nm

700 nm

594 nm

answer is D.

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Detailed Solution

$E = \frac{242 \times 10^{3}}{6.023 \times 10^{23}} = \frac{h c}{λ}$

$= \frac{6.626 \times 3 \times 6.023 \times 10^{- 3}}{242 \times 10^{3}}$

$= 0.4947 \times 10^{- 6} m$

$λ = 494.7 m m .$

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