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Q.

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates E, is :

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a

$\frac{1}{2} ε_{0} E^{2} / Ad$

b

$ε_{0} E^{2} Ad$

c

$\frac{1}{2} ε_{0} E^{2} Ad$

d

$ε_{0} E^{2} / Ad$

answer is A.

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Detailed Solution

Energy required = ${CV}^{2} = (\frac{{Aε}_{0}}{d}) (Ed) = {Aε}_{0} E^{2} d$

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