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Q.

The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283 kJ {mol}^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is :

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a

$- 110.5 kJ$

b

$676.5 kJ$

c

$110.5 kJ$

d

$- 676.5 kJ$

answer is D.

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Detailed Solution

The formation of carbon monoxide gas takes place as,

$C (gr) + \frac{1}{2} O_{2} (g) ⟶ CO (g)$

$\begin{aligned} Δ H_{Reaction} = Δ H_{C} (Re) - Δ H_{C} (\Pr) \\ = - 393.5 + 283 = - 110.5 kJ \end{aligned}$

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