Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

The enthalpies of formation of Al2O3(s) and  Fe2O3(s) are 1670 kJ mol1 and 834 kJ mol1respectively. The enthalpy change of the reaction Fe2O3(s)+Al(s)Al2O3(s)+2Fe(s) would be

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

836 kJ mol1

b

2504 kJ mol1

c

836 kJ mol1

d

2504 kJ mol1

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

ΔrH=ΔfHAl2O3,sΔfHFe2O3,s=(1670+834) kJ mol1=836 kJ mol1

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon