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Q.

The enthalpies of HCl, NaOH, NaCl and H2O are –120, –82, –148 and –68 K.Cals. respectively. Δ H of the following reaction is HCl + NaOH → NaCl + H2O

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a

–18 K.Cals

b

–28.7 K.Cals

c

–14 K.Cals

d

–57.3 K.Cals

answer is D.

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Detailed Solution

∆rH=∑ Hpro-∑ Hreact

= (-148-68) - (-120-82) = - 14 K.Cals

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