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The enthalpies of solution for copper sulphate penta hydrate and anhydrous copper sulphate are $- 11.7 k J m o l^{- 1}$ and $- 65.5 k J m o l^{- 1}$ respectively. The hydration enthalpy of anhydrous copper sulphate is

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$- 53.8 k J m o l^{- 1}$

$+ 77.2 k J m o l^{- 1}$

$+ 53.8 k J m o l^{- 1}$

$- 77.2 k J m o l^{- 1}$

answer is A.

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Detailed Solution

$C u S O_{4} .5 H_{2} O (s) + a q \to C u S O_{4} (a q);$

$Δ H_{s o l} = - 11.7$

$C u S O_{4} (s) + a q \to C u S O_{4} (a q);$

$Δ H_{s o l} = - 65.6 k J . m o l^{- 1}$

$\begin{array}{l} ∴ C u S O_{4} (s) + 5 H_{2} O (l) \to C u S O_{4} .5 H_{2} O (s) \\ Δ H = - 65.5 + 11.7 \\ = - 53.8 k J m o l^{- 1} \end{array}$

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