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Q.

The enthalpy and entropy change of trimerization of gas 3A(g)A3(g) in gas phase 300 K at 100 kJ/mole and 400J/K mole  respectively. The enthalpy of vapourisation for liquids A and A3 are 25 kJ/ mole and  50 kJ/mole  respectively. If the boiling points of A and A3 are 300 K and 400 K respectively

Given : CpmA3(g)=CpmA3(l), dA(l)=1.2 g/ml

dA3(l)=1.5 g/ml, molar mass of A = 20 gram

Assume : Density of A3(l) and A(l) are independent of pressure.

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a

ΔH for trimerisation in liquid phase at 300 K=125 kJ mol1

b

ΔS for trimerisation in liquid phase at 300 K=275 kJ mol1

c

At standard state of 300 K ΔG of the reaction3A(l)A3(l) is 7500J

d

The equilibrium pressure of the reaction:

3A(l)A3(l) is 7.501×108Pa at 300 K

answer is C, D.

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Detailed Solution

3A(g)A3(g); ΔH=100kJ/mole

ΔS=400 kJ/mole

ΔHvap (A,l)=25kJ/mole, ΔSvapA3,l=50 kJ/mole

Molar mass of A=20 g

CPm,A3(g)=CPm, A3(l); dA(l)=1.2 g/mL;dA3(i)=1.5 g/mL

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