The enthalpy change for the reaction of 50 mL of acetylene with 150 mL of $H_{2}$ to form ethane at 5 bar pressure is -1.2 kJ. Calculate $Δ U$ for the process.

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-1.4 kJ

-1.25 kJ

-1.3 kJ

-1.15 kJ

answer is D.

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Detailed Solution

$\begin{array}{ll} C_{2} H_{2} (g) + 2 H_{2} (g) ⟶ C_{2} H_{6} (g) \\ 50 150 & v_{f} = 200 \\ - 50 50 & v_{f} = 100 \\ \begin{aligned} - 1200 = Δ U + 5 \times (100 - 200) \times 10^{- 3} \times 100 \\ Δ U = - 1150 . \end{aligned} \end{array}$

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