Q.

The enthalpy changes for the following processes are listed   below : 
Cl2(g)2Cl(g)     242.3kJmol1 I2(g)2I(g)           151.0kJmol1 ICl(g)I(g)+Cl(g)   211.3kJmol1 I2(s)I2(g)                 62.76kJmol1
Given that the standard states for iodine and chlorine are  I2(s) and Cl2(g)the standard enthalpy of formation for ICI(g)  is :

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a

+244.8kJmol1

b

+16.8kJmol1

c

16.8kJmol1

d

14.6kJmol1

answer is A.

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Detailed Solution

I2(s)+Cl2(g)2ICl(g) ΔrH=ΔH(I2(s)I2(g))+ΔHII+ΔHClClΔHICl =151.0+242.3+62.762×211.3=33.46 DfH(ICl)=33.462=16.73kJ/mol

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