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Q.

The enthalpy of combustion of propane, graphite and dihydrogen at 298 K are: –2220.0 kJ mol^–1, – 393.5 kJ mol^–1 and –285.8 kJ mol^–1 respectively. The magnitude enthalpy of formation of propane (C₃H₈) is………kJ mol^–1. (Nearest integer)

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answer is 104.

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Detailed Solution

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from the values of combustion of propane graphite and hydrogen we have to calculate the heat of formation of propane

$3 C_{(gr)} + 4 H_{2 (g)} \to C_{3} H_{8 (g)}$

$= - 103.7 kJ {mol}^{- 1}$

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The enthalpy of combustion of propane, graphite and dihydrogen at 298 K are: –2220.0 kJ mol–1, – 393.5 kJ mol–1 and –285.8 kJ mol–1 respectively. The magnitude enthalpy of formation of propane (C3H8) is………kJ mol–1. (Nearest integer)