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Q.

The enthalpy of dissolution of BacI2(s) and BaCl22H2O(s) are -20.6 and 8.8 KJ mol-1 respectively. Calculate enthalpy of hydration for given reaction:

BaCl2(s)+2H2OBaCl22H2O(s)

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a

-29.4 kJ 

b

-35.4 kJ 

c

-24.4 kJ

d

15.2 kJ

answer is A.

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Detailed Solution

Enthalpy of hydration = enthalpy of dissolution of BacI2(s)  enthalpy of dissolution of  BaCl22H2O(s)

 Enthalpy of hydration

20.68.8=29.4kJ

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