The enthalpy of formation of H₂O(1) is - 290 kJ / mol and enthalpy of neutralization of strong acid with strong alkali is - 56 kJ / equiv. what is the enthalpy of formation of OH^- $(aq)? Given Δ_{form} H (H^{+}, aq) = 0$

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

- 346 kJ / mol

- 234 kJ / mol

- 178 kJ / mol

- 334 kJ / mol

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H_{1} = - 290 kJ$

$\begin{array}{l} H^{+} + {OH}^{-} \to H_{2} O; Δ H_{2} = - 56 kJ \\ \frac{1}{2} H_{2} \to H^{+} (aq); Δ H = 0 \\ ∴ \frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to {OH}^{-} (aq) Δ_{r} H \\ Δ_{r} H = - 290 + 56 = - 234 kJ / mol \end{array}$

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!