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The enthalpy of gas phase trimerization of one mole of gaseous formaldehyde in (kJ/mole)

Bond energies (kJ/mole)
Given:

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- 20

- 50

- 10

- 60

answer is A.

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Detailed Solution

$ΔH = 6 \times 410 + 700 \times 3 - 6 \times 410 - 6 \times 360 ΔH = 60$

- 60 for 3 moles

$∴$ For 1 moles = -20 kJ/mole

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