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The enthalpy of hydration of the $F e^{2 +}$ ion is $11.4 k . c a l / m o l$ higher than would be expected if there were no crystal field stabilization energy. Assuming the aqua complex to be high- spin, estimate the magnitude of $Δ$ for ${[F e {(H_{2} O)}_{6}]}^{2 +}$

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answer is 28.5.

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Detailed Solution

CFSE for the d⁶ weak field ion is $- 0.4 Δ .$ The $Δ H_{h y d}$ is higher because the energy of the complex is lowered by that much, $- 11.4 k . c a l / m o l .$
CFSE= - 11.4k.cal/mol
$= 0.4 Δ$

$∴ Δ = 28.5 k . c a l / m o l$

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