The enthalpy of neutralisation of HCl with NaOH is 57.3 kJ eq^-1. If 0.6 moles of NaOH is mixed with 0.2 moles of HCl, the amount of heat liberated is

57.3 kJ is the heat liberated when I mol of HCl is neturalised by 1 mole of NaOH producing one mole of H₂O
$\therefore$ for the neutralisation of 
0.2 NaOH + 0.2 HCl = 0.2 NaCl + 0.2H₂O
the heat liberated = 0.2x57.3=11.46kJ

HCl is limiting reagent