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The enthalpy of neutralization of a strong monobasic acid by a strong monoacidic base is -13700 cal. A certain monobasic weak acid is $α$ pecrcent ionized in a molar solution. If the enthalpy of ionization of the weak acid is 5000 cal/mole and the enthalpy of neutralization of one molar solution of the weak acid is -9700 cal, then $α =$

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answer is 20.

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Detailed Solution

$Δ H_{s t r o n g a c i d} = - 13700 Δ H_{w e a k a c i d} = - 9700 Δ H_{i o n i s a t i o n} = - 9700 - (- 13700) = 4000 c a l 1 m o l e \to 5000 c a l ? \to 4000 c a l$

Moles to be dissociated $= \frac{4000}{5000} = 0.8 m o l e$
Degree of dissociation $= 1 - 0.8 = 0.2$

$\Rightarrow 20 %$

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