The enthalpy of vaporization of liquid is 30 KJ/mol and entropy of vaporization is 75 ${\mathrm{Jk}}^{-1}{\mathrm{mole}}^{-1}$. The boiling point of the liquid at 1atm is 

 ∆H = 30 KJ/mole, ∆S = 75 ${\mathrm{Jk}}^{-1}{\mathrm{mole}}^{-1}$

$\begin{array}{l}\mathrm{\Delta S}=\frac{\mathrm{\Delta H}}{\mathrm{T}}\\ 75=\frac{30\times {10}^3}{\mathrm{T}}\\ \mathrm{T}={400}^{ }\mathrm{k}\end{array}$