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Q.

The enthalpy of vaporization of water at 100 °C is $37.3 kJ {mol}^{- 1}$ . What will be the value of entropy of vaporization?

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a

$0.0373 kJ K^{- 1} {mol}^{- 1}$

b

$37300 kJ K {mol}^{- 1}$

c

$100 J K^{- 1} {mol}^{- 1}$

d

$50 J K^{- 1} {mol}^{- 1}$

answer is D.

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Detailed Solution

$Δ S = Δ H / T = (37300 J {mol}^{- 1}) / (373 K) = 100 {JK}^{- 1} {mol}^{- 1}$

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