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Q.

The entropy change of argon is given to a good approximation by the expression : 

Sm/JK−1mol−1=36+20ln⁡T/K

Calculate the change in Gibbs free energy of one mole of argon gas when it is heated from 300 K to 400 Kat constant pressure. Express your answer excluding sign and decimal places

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answer is 15.

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Detailed Solution

dG=VdP−SdTΔG=−∫300400 [36+20ln⁡T]dT

=−36(400−300)−20(Tln⁡T−T)300400=−3.6−11.71=−15.31

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